help@askiitians.com

+91-735-322-1155

Integral Calculus> Integrate ∫(1+cos4x)/(cotx – tanx) dx...

question mark

Integrate
∫(1+cos4x)/(cotx – tanx) dx

Lovey , 11 Years ago

Grade 12

1 Answers

Jitender Singh

Ans:
Hello Student,
Please find answer to your question below

$I = \int \frac{1+cos4x}{cotx - tanx}dx$
$I = \int \frac{1+cos4x}{\frac{cosx}{sinx} - \frac{sinx}{cosx}}dx$
$I = \int \frac{(1+cos4x).sinx.cosx}{cos^{2}x-sin^{2}x}dx$
$I = \int \frac{(2cos^{2}2x).sinx.cosx}{cos^{2}x-sin^{2}x}dx$
$I = \int \frac{(cos^{2}2x).sin2x}{cos{2}x}dx$
$I = \int cos2x.sin2xdx$
$I = \frac{1}{2}\int 2cos2x.sin2xdx$
$I = \frac{1}{2}\int sin4xdx$
$I = \frac{-cos4x}{8} + c$

Approved

Last Activity: 11 Years ago

LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

Full Live Access

Study Material

Live Doubts Solving

Daily Class Assignments

The area of a square field is 640000cm².what is its area in hectares

integral calculus

1 Answer Available

Last Activity: 3 Years ago

Please solve this integration. I am facing difficulty in it
How to solve this. Please solve anyone. Humble request

integral calculus

1 Answer Available

Last Activity: 3 Years ago

Using laplace transform, solve d²y/dt²+ dy/dt = t² +2t given that y=4 and y’=-2 and t=0

integral calculus

1 Answer Available

Last Activity: 3 Years ago

If 4th term of an A.p is zero, show that the 8th term is double the 6th term

integral calculus

1 Answer Available

Last Activity: 3 Years ago

View all Questions