0

Guest

Courses New

Integral (x+2)dx/(2x^2 +4x+3)^2 plz solve I m very confused

Integral (x+2)dx/(2x^2 +4x+3)^2 plz solve I m very confused

Grade:

1 Answers

Khimraj
3007 Points
6 years ago
I = ∫(x+2)dx/(2x2 +4x+3)2
put 2x2 + 4x +3 = t
then (4x + 4)dx = dt
(2x + 2)dx = dt/2
Then I = ½∫dt/t2 = ½(-1/t) + c
So I = -½(1/(2x2 + 4x +3)) +c.
Hope it clears. If you like answer then please approve it.

Think You Can Provide A Better Answer ?

Other Related Questions on Integral Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More