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integral one divided by 1+cosx
limits are 0 to pie/4

Ranga Manchikanti , 9 Years ago
Grade 12th pass
anser 1 Answers
Arijit
1/1+cosx=1/(1+2cos2x/2-1)=1/2sec2x/2 
let tan(x/2)=z
take diff at both sides
½ sec2x/2dx=dz
now∫0(pi/4)dz=[z]0(pi/4)=[tan(x/2)]0(pi/4)=tan(pi/8)
Last Activity: 9 Years ago
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