integral o to π/2 tanx/1+m²tan²x....Solve this......Provide solution fast

Question

Soumalya Sahoo · Answer

0 to π/2 tanxdx/(1 +m^2tan^2x)=0 to π/2 (sinx/cosx)dx/((cos^2x+m^2 sin^2x)/cos^2x)=0 to π/2 sinxcosxdx/(cos^2x + m^2(1-cos^2x))Put cosx=t dt =-sinxdx and limit changes to 1 to 01 to 0 -tdt/(t^2 + m^2(1-t^2))= 0 to 1 tdt/(t^2(1-m^2)+m^2)= 1/2(1-m^2) 0 to 1 2t(1-m^2)dt/(t^2(1-m^2)+m^2)=1/2(1-m^2)[ln(t^2(1-m^2)+m^2)] from 0 to 1=1/2(1-m^2)[0-2lnm]=lnm/(m^2-1)

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

integral o to π/2 tanx/1+m²tan²x....Solve this......Provide solution fast

integral o to π/2 tanx/1+m²tan²x....Solve this......Provide solution fast

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Integral Calculus

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship