Integral 0 to 102 [tan^-1]dx [X] is the largest integer not exceeding x

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Aditya Gupta · Answer

just put tan inverse x = y or x= tany or dx=sex^2ydy now integral becomes 0 to tan inverse(102) [y]sec^ydy split this integral as 0 to 1 + 1 to tan inverse(102) from 0 to 1 [y]=0 from 1 to tan inverse(102), [y]=1 so, answer is 102-tan1

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Integral 0 to 102 [tan^-1]dx [X] is the largest integer not exceeding x

Integral 0 to 102 [tan^-1]dx [X] is the largest integer not exceeding x

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