integ 0 to π [sin ¹°°x.cos ??x] dx

                    
let I =integral of 0 to p sin ¹°°xcos x dx
   I =integral of 0 to p sin ¹°°(p-x)cos(p-x )dx
     =-integral of 0 to p sin ¹°°xcos x dx
     = -I
    2I=0
     I=0


Thanks & Regards
Parvez Ali
askIITians Faculty
Btech
ISM Dhanbad