Indefinite integration 1/(x^4-1)^2 dxWhat to write it is saying question must not be less than 50 charcaters

Write it as 1/(x^2+1)^2(x-1)^2(x+1)^2Then use partial fractions Then you get1/(4 (x^2 + 1)) + 1/(4 (x^2 + 1)^2) + 3/(16 (x + 1)) + 1/(16 (x + 1)^2) - 3/(16 (x - 1)) + 1/(16 (x - 1)^2) then integrate