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if integration of (a/(b+ce^x)) is = -k(ln(mod(b+ce^x)-x)+d then what is the k value?
integral a/(b+ce^x) dxput b+ce^x=ton diff.w.r.t. x, we getce^x dx=dtintegral adt/ce^x.t=integral a dt/t(t-b)=a/bintegral[1/(t-b)-1/t]dt=a/b[log(mod(t-b))-log(mod(t))]+d=a/b[log(mod(ce^x))-log(mod(b+ce^x))]+d=a/b[cx-log(mod(b+ce^x))]+d=-a/b[log(mod(b+ce^x))-cx]+dcomparing the result to the right hand side of the question , it is clear that K=a/b Ans.Thanks & RegardsRinkoo GuptaAskIITians Faculty
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