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if f ‘(x) = a sin x + b cos x and f ‘(0) = 4 , f(0) = 3 , f(pi/2) =5 find f(x)
Dear student f'(0) = 4 = bf(x) = - a cos x + b sinx + cNowf(0) = 3 = -a + cf(π/2) = 5 = b + cHence c = 1And a = -2 Hence f(x) = 2 cos x + 4 sin x +1
Dear student Please refer the study material and examplehttps://www.askiitians.com/iit-jee-algebra/set-relations-functions/functions/Good Luck
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