If 1/3 ＜= X 2 ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x 2 + 1) , then what is the integral formula of this function?

Question

If 1/3 ＜= X 2 ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x 2 + 1) , then what is the integral formula of this function?

Aditya Gupta · Answer

we know the following integral : ∫dx/(x^2+1)= arctanx +C or tan-1(x) + C so, final ans on simplifying would be 1/6. kindly approve :=))

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If 1/3 ＜= X 2 ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x 2 + 1) , then what is the integral formula of this function?

If 1/3 ＜= X² ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x² + 1) , then what is the integral formula of this function?

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If 1/3 ＜= X 2 ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x 2 + 1) , then what is the integral formula of this function?

If 1/3 ＜= X2 ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x2 + 1) , then what is the integral formula of this function?

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If 1/3 ＜= X² ＜= 1, then either root(3)/ 3 ＜= X ＜= 1 or -1 ＜= X ＜= -root(3)/ 3. If the function X = 1 / (x² + 1) , then what is the integral formula of this function?