I need to integrate this question That is the question ∫1/(x-b)²(x-a)²

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I need to integrate this question That is the question ∫1/(x-b)²(x-a)²

Amit · Answer

Multiply and divide by (b-a)² and then write (b-a)² as ((x-a)-(x-b))² open the square and first two terms are easily integrable ..in last term use partial fraction .

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I need to integrate this question That is the question ∫1/(x-b)²(x-a)²

I need to integrate this question That is the question

∫1/(x-b)²(x-a)²

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I need to integrate this question That is the question ∫1/(x-b)²(x-a)²

I need to integrate this question That is the question ∫1/(x-b)²(x-a)²

1 Answers

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Other Related Questions on Integral Calculus

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I need to integrate this question That is the question

∫1/(x-b)²(x-a)²