Grade 12th passIntegral Calculus
How to solve Integration of one upon square root of log x
1 Answer
Nandana
log(x)=y
x= e^y
dx=e^y dy
∫ (1/ √y e^y dy it seems like Gamma function , which is in the form of ∫ x^(n-1) e^-x dx
take y=p
∫ 1/ √p e^-p (-dp) = -i ∫ 1/ √p e^-p dp = -i √π √log x + C
where ‘i’ is imaginary part ..
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