How to solve Integration of one upon square root of log x

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Nandana · Answer

log(x)=y x= e^y dx=e^y dy ∫ (1/ √y e^y dy it seems like Gamma function , which is in the form of ∫ x^(n-1) e^-x dx take y=p ∫ 1/ √p e^-p (-dp) = -i ∫ 1/ √p e^-p dp = -i √π √log x + C where ‘i’ is imaginary part ..

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How to solve Integration of one upon square root of log x

How to solve Integration of one upon square root of log x

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