0

Guest

Courses New

How to solve Integration of one upon square root of log x

How to solve Integration of one upon square root of log x

Grade:12th pass

1 Answers

Nandana
110 Points
7 years ago
      log(x)=y
      x= e^y
      dx=e^y dy
    ∫ (1/  √y e^y dy  it seems like Gamma function  , which is in the form of  ∫ x^(n-1) e^-x dx
     take y=p
    ∫ 1/ √p e^-p (-dp) = -i ∫ 1/ √p e^-p dp = -i √π  √log x  + C
          where ‘i’ is imaginary part ..
     

Think You Can Provide A Better Answer ?

Other Related Questions on Integral Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More