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Grade: 12

                        

How to integrate ∫(cos2x-cos2a)/(cosx-cosa)dx where a is constant

2 years ago

Answers : (3)

Arun
24742 Points
							
∫(cos 2x - cos 2a) / (cos x - cos a) dx 
= ∫((2cos^2 x - 1) - (2cos^2 a - 1)) / (cos x - cos a) dx 
= ∫(2 cos^2 x - 2 cos^2 a) / (cos x - cos a) dx 
= ∫[2(cos x - cos a)(cos x + cos a)] / (cos x - cos a) dx 
= ∫2(cos x + cos a) dx 
= 2 sin x + x cos a + c.
2 years ago
Rakshit Puri
15 Points
							
Hsbs
 
∫(cos 2x - cos 2a) / (cos x - cos a) dx 
= ∫((2cos^2 x - 1) - (2cos^2 a - 1)) / (cos x - cos a) dx 
= ∫(2 cos^2 x - 2 cos^2 a) / (cos x - cos a) dx 
= ∫[2(cos x - cos a)(cos x + cos a)] / (cos x - cos a) dx 
= ∫2(cos x + cos a) dx 
= 2 sin x + 2x cos a + c
2 years ago
ankit singh
askIITians Faculty
596 Points
							
= 2 sin x + 2x cos a + c= ∫2(cos x + cos a) dx = ∫[2(cos x - cos a)(cos x + cos a)] / (cos x - cos a) dx = ∫(2 cos^2 x - 2 cos^2 a) / (cos x - cos a) dx ∫((2cos^2 x - 1) - (2cos^2 a - 1)) / (cos x - cos a) dx 
3 months ago
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