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Grade: 12th pass

                        

How to find integration of tan3x.tan2x.tanx.? Is there any easy way to solve it

4 years ago

Answers : (1)

Vikas TU
12154 Points
							
use standard identities first and then reduc this to an easy expression eqn. then integearte it.
Use, tan(A+B) = (tanA + tanB)/(1 – tanAtanB)
tanAtanB = 1 –  (tanA + tanB)/tan(A+B)
for tan2x and tanx,
 
tan2x.tanx = 1  – (tanx + tan2x)/tan3x = > (tan3x – tanx – tan2x)/tan3x
TThus the expression reduces to:
tan3x*(tan3x – tanx – tan2x)/tan3x
or
  dI = (tan3x – tanx – tan2x) dxNow u can integerate easily.
 
 
 
 
4 years ago
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