Integral Calculus> hey image attached please tell the method...
2 Answers
Last Activity: 10 Years ago
Ans:
Hello student,
Please find the answer to your question below![L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latexl_frac34_frac34_frac1100_frac34_frac2100_frac34_frac99100.jpg)
[t] = 0, 0 <=t < 1
[t] = 1, 1 <= t < 2
Now looking at the problem in hand![[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latex_frac34_fracx10000ltxlt25.jpg)
![[\frac{3}{4}+\frac{x}{100}] = 1, 25 <= x < 99](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latex_frac34_fracx100125ltxlt99.jpg)
There are total 100 term in L out of which 25 terms are zero.
Rest all the terms are equal to 1.
So the sum is 75.
Last Activity: 10 Years ago
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