Integral Calculus> hey image attached please tell the method...
1 Answers
Last Activity: 10 Years ago
Ans:
Hello student,
Please find the answer to your question below![L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latexl_frac34_frac34_frac1100_frac34_frac2100_frac34_frac99100.jpg)
[t] = 0, 0 <=t < 1
[t] = 1, 1 <= t < 2
Now looking at the problem in hand![[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latex_frac34_fracx10000ltxlt25.jpg)
![[\frac{3}{4}+\frac{x}{100}] = 0, 25 <= x < 99](https://files.askiitians.com/cdn1/cms-content/common/latex.codecogs.comgif.latex_frac34_fracx100025ltxlt99.jpg)
There are total 100 term in L out of which 25 terms are zero.
Rest all the terms are equal to 1.
So the sum is 75.
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
Last Activity: 2 Year ago(s)
