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find the minimum value of f(x)=(x²-x+1)÷(x²+x+1)

lokesh palingi , 11 Years ago
Grade 12
anser 1 Answers
Sunil Raikwar

Last Activity: 11 Years ago

y=(x^2-x+1)/(x^2+x+1)

yx^2+yx+y=x^2-x+1
(y-1)x^2+(y+1)x+y-1=0
since x belong to R
Therefore, Discriminant>=0
(y+1)^2-4(y-1)(y-1)>=0
y^2+2y+1-4y^2+8y-4>=0
-3y^2+10y-3>=0
3y^2-10y+3<=0
(y-3)(3y-1)<=0
y belong to 1/3 to 3 so minimum value is 1/3

Thanks & Regards
Sunil Raikwar
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