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find the maximum value of f(x) where f(x)=integration of (2t−t²+5)dt from (0,x)
Find df/dx :df/dx = 2x - x2+ 5 = 0The roots of this equation : x = 1 + root(6), 1- root(6)d/dx ( df/dx) = 2 - 2xIt is negative for the first root x = 1 + root(6)Hence the maximum value can be found out by putting x = 1 + root(6) in the integral. Integrate the integral and find it.Thanks & RegardsBharat BajajaskIITians FacultyIIT Delhi
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