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find the maximum value of f(x) at f(x)=(2t-t²+5)dt from(0,p)

lokesh palingi , 10 Years ago
Grade 12
anser 1 Answers
Sher Mohammad

Last Activity: 10 Years ago


f(x)=?(2t-t^2+5)dt=[t^2-(t^3)/3+5t](between 0 to p)

=x^2-(x^3)/3+5x




Thanks & Regards
Sher Mohammad,
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B.Tech.
IIT Delhi.

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