0

Guest

Courses New

find the Integration of the function f(x)=||x-2|+1| in interval [-1,1]? and also find area of Integral function?

find the Integration of the function f(x)=||x-2|+1| in interval [-1,1]?
and also find area of Integral function?

Grade:12

2 Answers

Parvez ali
askIITians Faculty 47 Points
9 years ago
if -1=<x<=1 then (x-2)<0 thus mod(x-2)=(2-x)
so mod(mod(x-2)+1)=mod(3-x)
if -1=<x<=1 then (3-x)>0 thus mod(3-x)=3-x
integration=(3x-x2/2)-11
=(3-1/2)-(-3-1/2)
=6
area=integration=6
Thanks & Regards
Parvez Ali
askIITians Faculty
B-tech
ISM Dhanbad


Pradeeep Anand
40 Points
9 years ago
plot of above function: the function f(x) = x-2+1=x-1 for x>2 = -x+2+1=-x+3 for x<2 } )f(x)dx=)x-1 (between 2 to x(x>2))=(1/2)x^2-x =)-x+3(between x to 2(x<2))=(1/2)(-x^2)+3x

Think You Can Provide A Better Answer ?

Other Related Questions on Integral Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More