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find the integration of cotxlogsinx dx.
pls answer as fast as you can. 

Chaitanya Shrivastav , 7 Years ago
Grade 12th pass
anser 1 Answers
sanad

Last Activity: 7 Years ago

Let  log(sinx)=t
differentiate w.r.t “x”
\frac{1}{sinx}*cosx dx=dt
cotx  dx  =  dt
substitute  these  values
\int t dt
 = t2  /2
put the value of t again
=  (log(sinx))2    /  2

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