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Grade: 12th pass

                        

Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)

Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)

one year ago

Answers : (3)

Arun
25768 Points
							
Dear student
 
To find the tangents to a give curve,differentiate the the give curve....
On differentiating...we get slope of the tangent..
 
Differentiating with respect to x,
2/3(x-1/3) + 2/3(y-1/3) dy/dx = 0
 
dy/dx = -x-1/3/y-1/3
NOW FIND slope at (h,k) and then write equation of tangent
one year ago
Vikas TU
14149 Points
							
Dear student 
Please follow this link 
Good Luck 
one year ago
Aditya Gupta
2074 Points
							
the correct answer is 
replace x^2 by xh, and y^2 by yk
so, eqn of tangent is 
 xh/3+yk/3=a^2/3 (slope = – h/k)
normal can be written as
y – k= m(x – h)
where m*( – h/k)= – 1
or m= k/h
or yh – kh= kx – kh
or y= kx/h
kindly approve :))
one year ago
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