Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)

Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)

Grade:12th pass

3 Answers

Arun
25763 Points
one year ago
Dear student
 
To find the tangents to a give curve,differentiate the the give curve....
On differentiating...we get slope of the tangent..
 
Differentiating with respect to x,
2/3(x-1/3) + 2/3(y-1/3) dy/dx = 0
 
dy/dx = -x-1/3/y-1/3
NOW FIND slope at (h,k) and then write equation of tangent
Vikas TU
14149 Points
one year ago
Dear student 
Please follow this link 
Good Luck 
Aditya Gupta
2075 Points
one year ago
the correct answer is 
replace x^2 by xh, and y^2 by yk
so, eqn of tangent is 
 xh/3+yk/3=a^2/3 (slope = – h/k)
normal can be written as
y – k= m(x – h)
where m*( – h/k)= – 1
or m= k/h
or yh – kh= kx – kh
or y= kx/h
kindly approve :))

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free