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Grade: 12th pass
        
Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)
one month ago

Answers : (3)

Arun
23338 Points
							
Dear student
 
To find the tangents to a give curve,differentiate the the give curve....
On differentiating...we get slope of the tangent..
 
Differentiating with respect to x,
2/3(x-1/3) + 2/3(y-1/3) dy/dx = 0
 
dy/dx = -x-1/3/y-1/3
NOW FIND slope at (h,k) and then write equation of tangent
one month ago
Vikas TU
9762 Points
							
Dear student 
Please follow this link 
Good Luck 
one month ago
Aditya Gupta
1805 Points
							
the correct answer is 
replace x^2 by xh, and y^2 by yk
so, eqn of tangent is 
 xh/3+yk/3=a^2/3 (slope = – h/k)
normal can be written as
y – k= m(x – h)
where m*( – h/k)= – 1
or m= k/h
or yh – kh= kx – kh
or y= kx/h
kindly approve :))
one month ago
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