Find the equation of tangent and normal of curve x^2/3+y^2/3=a^2/3 at (h,k)
Sebika karki , 5 Years ago
Grade 12th pass
Integral Calculus> Find the equation of tangent and normal o...
3 Answers
Arun
Last Activity: 5 Years ago
Dear student
To find the tangents to a give curve,differentiate the the give curve....
On differentiating...we get slope of the tangent..
Differentiating with respect to x,
2/3(x-1/3) + 2/3(y-1/3) dy/dx = 0
dy/dx = -x-1/3/y-1/3
NOW FIND slope at (h,k) and then write equation of tangent
Vikas TU
Last Activity: 5 Years ago
Dear student
Please follow this link
Good Luck
Aditya Gupta
Last Activity: 5 Years ago
the correct answer is
replace x^2 by xh, and y^2 by yk
so, eqn of tangent is
xh/3+yk/3=a^2/3 (slope = – h/k)
normal can be written as
y – k= m(x – h)
where m*( – h/k)= – 1
or m= k/h
or yh – kh= kx – kh
or y= kx/h
kindly approve :))
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