Find the area of the surface of solid of revolution generated revolving the parabola
Y2=4ax, o≤x≤ 3a about x-axis

Dear ram,A= int[a,b] (Ydx)Y=sqrt (4ax)then,A = int[0,3] (sqrt (4ax)) dxA= sqrt (4a) int[0,3] sqrt (x) dxA= 4sqrt(3a)