Find area enclosed between curve y=x²+2 and y=x³ , line x=1,x=2.

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Arun · Answer

Dear student Area = integration from 1 to 2 (x 3 – x 2 – 2) = (x^4/4 – x^3 /3 – 2x) from 1 to 2 = 4 - 8/3 – 4 – ¼ + 1/3 + 2 = 19/3 – 83/12 = 7/12

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Find area enclosed between curve y=x²+2 and y=x³ , line x=1,x=2.

Find area enclosed between curve y=x²+2 and y=x³ , line x=1,x=2.

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Find area enclosed between curve y=x²+2 and y=x³ , line x=1,x=2.

Find area enclosed between curve y=x²+2 and y=x³ , line x=1,x=2.

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