evalute intigration of sec x cosec x / lon (tan x) dx how can i find its answer

Hey..its very simple....Put log(tanx) = t...So....1/ tanx . Sec^2x .dx = dt....Cotx.sec^2x dx dt...Cosx.cosecx.sec^2dx =dt... [ cotx = cosx/sinx = cosx.cosecx ]So.... Cosecx . Secx dx = dt...So...required integration is...Int of 1/t .dt.... = logt...so answer is log[log(tanx)]...Hope you have understood this.....