MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        Evaluate: xtan^2(x)dx from 0 to pi/3. Please i need help
10 months ago

Answers : (1)

Arun
14829 Points
							
Dear John
 

To calculate integral of xtan^2x.

We now that tan^2x = sec^2x-1.

Therefore Int xtan^2x dx = Int x*(sec^2x - 1)dx

Int xtan^2x dx= Int xsec2xdx - Int xdx

Int xtan^2x dx = Intx*sec^2xdx - x^2/2....(1)

Int xsec^2x dx = xtanx - Int{x'tanx}dx.

Int xtanx dx =  xtanx - Int tanx dx

Int xtanx = xtanx+log(cosx) + C. Substituting this in (1) we get:

Int x tan^2x dx = xtanx + log(cosx) - x^2/2+C.

 

Now put limit from 0 to pi/3

(Pi/3)* sqrt(3)+ log(1/2) - pi²/18

 

Regards

Arun (askIITians forum expert)

10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 170 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details