Grade 12Integral Calculus

evaluate
∫ {x^3 – 3(x)^2 + 5x – 7 +x^2 a^x} / 2(x)^2 dx

taniska

11 Years agoGrade 12

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$I = \int \frac{x^3-3x^2+5x-7+x^2a^{x}}{2x^2}dx$
$I = \frac{1}{2}\int \frac{x^3-3x^2+5x-7+x^2a^{x}}{x^2}dx$
$I = \frac{1}{2}\int (x-3+\frac{5}{x}-\frac{7}{x^2}+a^{x})dx$
$I = \frac{1}{2}[\int xdx-\int 3dx+\int \frac{5}{x}dx-\int \frac{7}{x^2}dx+\int a^{x}dx]$
$I = \frac{1}{2}[\frac{x^2}{2}-\int 3dx+\int \frac{5}{x}dx-\int \frac{7}{x^2}dx+\int a^{x}dx]$
$I = \frac{1}{2}[\frac{x^2}{2}-3x+\int \frac{5}{x}dx-\int \frac{7}{x^2}dx+\int a^{x}dx]$
$I = \frac{1}{2}[\frac{x^2}{2}-3x+5lnx-\int \frac{7}{x^2}dx+\int a^{x}dx]$
$I = \frac{1}{2}[\frac{x^2}{2}-3x+5lnx+ \frac{7}{x}+\int a^{x}dx]$
$I = \frac{1}{2}[\frac{x^2}{2}-3x+5lnx+ \frac{7}{x}+\frac{a^{x}}{ln2}]+c$