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evaluate the following integral ∫ sin 2x / a^2 + b^2 sin^2 (x) dx

evaluate the following integral
∫ sin 2x / a^2 + b^2 sin^2 (x) dx

Grade:12

1 Answers

Sanjeev Kumar
24 Points
6 years ago
let a^2 + b^2 sin^2 (x) = t
b^2 sin 2x dx = dt
sin 2x dx = dt/b2
equating the the above value in 
∫sin 2x / a^2 + b^2 sin^2 (x) dx
we get 
∫dt/b2t
= 1/b∫dt/t
= 1/b2 log t
= 1/b2 log (a^2 + b^2 sin^2 (x)) 
 

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