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Grade 12Integral Calculus

evaluate the following integral
∫ sec x cosec x / log(tan x) dx

Profile image of taniska
11 Years agoGrade 12
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1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello student,
Please find the answer to your question below

I = \int \frac{secxcosecx}{log(tanx)}dx
log(tanx) = t
\frac{1}{tanx}sec^{2}xdx = dt
secxcosecxdx = dt
I = \int \frac{1}{t}dt
I = log(t)+c
I = log(log(tanx))+c