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question mark

evaluate the following integral
∫ (2 cos 2x + sec^2 (x)) / sin 2x + tan x – 5 dx

taniska , 11 Years ago
Grade 12
anser 1 Answers
Jitender Singh
Ans:
Hello student,
Please find the answer to your question below

I = \int \frac{2cos2x+sec^{2}x}{sin2x+tanx-5}dx
sin2x+tanx-5 = t
(2cos2x+sec^{2}x)dx = dt
I = \int \frac{dt}{t}
I = log(t) + c
I = log(sin2x+tanx-5) + c
Last Activity: 11 Years ago
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