Grade 12Integral Calculus
evaluate the following integral
∫ 1 + tan x / x + log sec x dx
evaluate the following integral
∫ 1 + tan x / x + log sec x dx
∫ 1 + tan x / x + log sec x dx
1 Answer
Sanjeev Kumar
- Let x + log Sec x = t
1 + 1/sec x ×sec x tan x dx = dt
= 1+ tan x dx =dt
equating the above value in
∫1 + tan x / x + log sec x dx
we get
∫dt/t
= log t
= log (x + sec x)
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