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question mark

evaluate the following integral
∫ 1 + cot x / x + log sin x dx

taniska , 11 Years ago
Grade 12
anser 1 Answers
Jitender Singh
Ans:
Hello student,
Please find the answer to your question below

I = \int \frac{1+cotx}{x+log(sinx)}dx
x+log(sinx) = t
(1+\frac{cosx}{sinx})dx = dt
(1+cotx)dx = dt
I = \int \frac{dt}{t}
I = log(t) + c
I = log(x+log(sinx)) + c
Last Activity: 11 Years ago
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