Evaluate limn->infinity (nasin2 (n!))/(n+1)Pls solve with steps and send as soon as possible
Evaluate limn->infinity (nasin2 (n!))/(n+1)
Pls solve with steps and send as soon as possible
Vinod Ramakrishnan Eswaran , 7 Years ago
Grade 12
Integral Calculus> Evaluate lim n->infinity (n a sin 2 (n!))...
1 AnswersAditya Gupta
when a is less than 1, the limit exists and equals zero, which can be seen by dividing the num and denom by n and then applying sandwich theorem on the num.
when a is greater than or equal to 1, the limit does not exist
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