Evaluate lim n-infinity (n a sin 2 (n!))/(n+1) Pls solve with steps and send as soon as possible

Question

Evaluate lim n->infinity (n a sin 2 (n!))/(n+1) Pls solve with steps and send as soon as possible

Aditya Gupta · Answer

when a is less than 1, the limit exists and equals zero, which can be seen by dividing the num and denom by n and then applying sandwich theorem on the num. when a is greater than or equal to 1, the limit does not exist

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Evaluate lim n->infinity (n a sin 2 (n!))/(n+1) Pls solve with steps and send as soon as possible

Evaluate lim_n->infinity (n^asin²(n!))/(n+1)
Pls solve with steps and send as soon as possible

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Evaluate lim n->infinity (n a sin 2 (n!))/(n+1) Pls solve with steps and send as soon as possible

Evaluate limn->infinity (nasin2 (n!))/(n+1)Pls solve with steps and send as soon as possible

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Evaluate lim_n->infinity (n^asin²(n!))/(n+1)
Pls solve with steps and send as soon as possible