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Grade 12Integral Calculus

evaluate
∫ cot^-1( sin 2x / 1 – cos 2x) dx

taniska

11 Years agoGrade 12

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello Student,
Please find answer to your question below

$I = \int cot^{-1}(\frac{sin2x}{1-cos2x})dx$
$I = \int cot^{-1}(\frac{2sinx.cosx}{2sin^2x})dx$
$I = \int cot^{-1}(\frac{cosx}{sinx})dx$
$I = \int cot^{-1}(cotx)dx$
$I = \int xdx$
$I = \frac{x^2}{2}+c$

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