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question mark

evaluate ∫ ax ex with respect to x
options
A . (ae)x
B. ( axex)/loga +logx
C.(ae)x/1+loga
D.(ae)x/logax

rangu meghana , 8 Years ago
Grade 12th pass
anser 1 Answers
Ritika Das
Let u=axex
du/dx=exaxloga+axex
         =exax(loga+1)
Therefore, dx=du/{exax(loga+1)}
So, ∫axex.dx = ∫axex.du/{exax(loga+1)}.......[putting value of dx from above in here]
            Answer is option C. 
Last Activity: 8 Years ago
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