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evaluate ∫ ax exwith respect to x options A . (ae)xB. ( axex)/loga +logxC.(ae)x/1+logaD.(ae)x/logax

rangu meghana , 7 Years ago
Grade 12th pass
anser 1 Answers
Ritika Das

Last Activity: 7 Years ago

Let u=axex
du/dx=exaxloga+axex
         =exax(loga+1)
Therefore, dx=du/{exax(loga+1)}
So, ∫axex.dx = ∫axex.du/{exax(loga+1)}.......[putting value of dx from above in here]
            Answer is option C. 

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