kartik kumar11 Years agoI = ∫(1+x)3/x1/2Put, x = t2 dx = 2t dtI = ∫(1+t2)3.2t dt/tI = 2∫(1 + t6 +2t2+2t4) dtI = 2(t + t7/7 +2t3/3 +2t5/5 +CI = 2(x1/2 + x7/2/7 + 2x3/2/3+ 2x5/2/5 +C