Integral Calculus

.∫(e200x+e202x)/(ex+e-x)dx.

sam

11 Years agoGrade

1 Answer

Jitender Singh

11 Years ago

Ans:
Hello Sudent,
Please find answer to your question below

$I = \int \frac{e^{200x}+e^{202x}}{e^{x}+e^{-x}}dx$
$I = \int \frac{e^{200x}}{e^{-x}}.\frac{1+e^{2x}}{e^{2x}+1}dx$
$I = \int e^{201x}.dx$
$I = \frac{e^{201x}}{201} + constant$

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.∫(e200x+e202x)/(ex+e-x)dx.

sam

1 Answer

Jitender Singh

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