MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
∫dx/(sin^4x+cos^4x)=
plese solve this.The answer should be in the form of tan 
9 months ago

Answers : (1)

Arun
23342 Points
							

I=∫(1/sin⁴x+cos⁴x)dx

Dividing numerator and denominator by cos⁴x

I=∫(sec⁴x/1+tan⁴x)dx

I=∫[(1+tan²x)sec²x/1+tan⁴x]dx

Now put tanx=t

sec²xdx=dt

I=∫(1+t²/1+t⁴)dt

I=∫[(1+1/t²)/(t²+1/t²)]dt

I=∫[(1+1/t²)/(t-1/t)²+2]dt

Now put (t-1/t)=z

(1+1/t²)dt=dz

I=∫dz/z²+(√2)²=(1/√2)tan-¹z/√2+c

=(1/√2)tan-¹(t-1/t)/√2+c

=(1/√2)tan-¹(tanx-cotx)/√2+c

9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details