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Grade: 12
        Definite integration question... Help please (question is in the attachment)
7 months ago

Answers : (1)

Adarsh
764 Points
							
Dear,
I=xsinx/1+cos2x dx............ 1
= (pi-x)sin(pi-x)/1+cos2(pi-x)...........2
Adding 1 and 2 we get,
2I=pi.sinx/1+cos2x
=> I= pi/2 .sinx/1+cos2x
now it can be solved by substitution method, take cosx=t 
After solving and putting the limits we get pi2/4 as Answer.
Hope that this will help ..
7 months ago
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