# Cos^4x + 1/ cotx - tanx................ # 1-x^7/ 1+ x^7 #.(2.718^x -1 / 2.718^x + 1)^1/2
# Cos^4x + 1/ cotx - tanx................
# 1-x^7/ 1+ x^7
#.(2.718^x -1 / 2.718^x + 1)^1/2
Shah Rutvi , 6 Years ago
Grade 12
Integral Calculus> # Cos^4x + 1/ cotx - tanx...................
1 AnswersArun
Last Activity: 6 Years ago
Dear student
Please ask only one question in one thread.
I=∫(1+cos4x)/(cotx-tanx) dx
I= ∫(1+ cos4x)sinx cosx/(cos2x-sin2x) dx
= ∫(1+ 2cos22x-1)sin2x/2cos2x dx
I= ∫cos2x sin2xdx
= 1/2 ∫ sin4xdx
= 1/8 [-cos4x] +c
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