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# Cos^4x + 1/ cotx - tanx................ #1-x^7/ 1+ x^7#.(2.718^x -1/ 2.718^x + 1)^1/2

Shah Rutvi , 5 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 5 Years ago

Dear student
 
Please ask only one question in one thread.
 
 

I=∫(1+cos4x)/(cotx-tanx) dx

I= ∫(1+ cos4x)sinx cosx/(cos2x-sin2x)  dx

  = ∫(1+ 2cos22x-1)sin2x/2cos2x  dx

I= ∫cos2x sin2xdx

   = 1/2 ∫ sin4xdx

   = 1/8 [-cos4x] +c

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