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f'(x)=sinx+xcosx/(sinx)^2=1/sinx(x)+xcos(x)/(sinx)^2f'(x)>0 for all x in 0 to p/4hence function in monotonically increasing.Sher MohammadB.Tech, IIT Delhi
f'(x)=sinx-xcosx/(sinx)^2
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