Can we integrate this by directly converting ({2x}-1)({3x}-1) into [2x][3x] ?

Question

Anish Singhal · Answer

No its fractional part of x so you cannot do this

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Can we integrate this by directly converting ({2x}-1)({3x}-1) into [2x][3x] ?

Can we integrate this by directly converting ({2x}-1)({3x}-1) into [2x][3x] ?

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Can we integrate this by directly converting ({2x}-1)({3x}-1) into [2x][3x] ?

Can we integrate this by directly converting ({2x}-1)({3x}-1) into [2x][3x] ?

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