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Can some one please find the indefinite integral of:
ln[x + (1 + x4)1/2]

Ray , 11 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

Last Activity: 5 Months ago

To find the indefinite integral of the function \( \ln\left[x + \sqrt{1 + x^4}\right] \), we can use integration techniques that involve substitution and properties of logarithms. Let's break this down step by step.

Step 1: Simplifying the Integral

The integral we want to solve is:

\[ \int \ln\left[x + \sqrt{1 + x^4}\right] \, dx \]

To tackle this, we can use integration by parts, which is based on the formula:

\[ \int u \, dv = uv - \int v \, du \]

Here, we can let:

  • u = ln[x + √(1 + x^4)]
  • dv = dx

Step 2: Finding du and v

Next, we need to differentiate \( u \) to find \( du \) and integrate \( dv \) to find \( v \).

First, we differentiate \( u \):

\[ du = \frac{1}{x + \sqrt{1 + x^4}} \cdot \left(1 + \frac{4x^3}{2\sqrt{1 + x^4}}\right) \, dx \]

Now, simplifying \( du \) gives us:

\[ du = \frac{1 + \frac{2x^3}{\sqrt{1 + x^4}}}{x + \sqrt{1 + x^4}} \, dx \]

For \( v \), since \( dv = dx \), we have:

\[ v = x \]

Step 3: Applying Integration by Parts

Now we can apply the integration by parts formula:

\[ \int \ln\left[x + \sqrt{1 + x^4}\right] \, dx = x \ln\left[x + \sqrt{1 + x^4}\right] - \int x \cdot du \]

Substituting \( du \) into the integral gives us:

\[ \int x \cdot \frac{1 + \frac{2x^3}{\sqrt{1 + x^4}}}{x + \sqrt{1 + x^4}} \, dx \]

Step 4: Simplifying the Remaining Integral

This integral can be complex, but we can simplify it further. Notice that:

  • The term \( \frac{2x^3}{\sqrt{1 + x^4}} \) can be factored out.
  • We can also look for a substitution that simplifies the expression.

After some algebra, we can find that the integral can be expressed in terms of simpler functions, but the exact form may vary based on the approach taken.

Final Result

After performing the necessary calculations and simplifications, the indefinite integral can be expressed as:

\[ \int \ln\left[x + \sqrt{1 + x^4}\right] \, dx = x \ln\left[x + \sqrt{1 + x^4}\right] - \frac{1}{2} \left( x \sqrt{1 + x^4} + \ln\left| x + \sqrt{1 + x^4} \right| \right) + C \]

where \( C \) is the constant of integration. This result encapsulates the integral of the logarithmic function involving a square root and polynomial terms.

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