# ax/\n-1/(bx/\n+c)

Sumit Majumdar IIT Delhi
8 years ago
Hello student,
Please confirm if the question is as follows:
$\int \frac{\frac{ax}{n-1}}{\frac{bx}{n+c}}$
If this is the question, the answer goes as follows:
$\frac{n+c}{n-1}\int\frac{ax}{bx}dx =\frac{a}{b}\frac{n+c}{n-1} \int dx=\frac{a}{b}\frac{n+c}{n-1}x$
Thanks & Regards
Sumit Majumdar,