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ax/\n-1/(bx/\n+c)

mayank , 11 Years ago
Grade
anser 1 Answers
Sumit Majumdar

Last Activity: 11 Years ago

Hello student,
Please confirm if the question is as follows:
\int \frac{\frac{ax}{n-1}}{\frac{bx}{n+c}}
If this is the question, the answer goes as follows:
\frac{n+c}{n-1}\int\frac{ax}{bx}dx =\frac{a}{b}\frac{n+c}{n-1} \int dx=\frac{a}{b}\frac{n+c}{n-1}x
Thanks & Regards
Sumit Majumdar,
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Ph.D,IIT Delhi
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