0

Guest

Courses New

Answer this question on relations and functions (JEE mains level).

Answer this question on relations and functions (JEE mains level).

Question Image
Grade:12

1 Answers

Abhishek
22 Points
5 years ago
Range of asinx ± bcosx is [-√a²+b², +√a²+b²] here a=1 & b=√3 then range is [-2,+2] +1 that equals [-2+1,+2+1]=[-1,3]

Think You Can Provide A Better Answer ?

Other Related Questions on Integral Calculus

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More