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Answer this question on relations and functions (JEE mains level).

Answer this question on relations and functions (JEE mains level).

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Grade:12

1 Answers

Abhishek
22 Points
6 years ago
Range of asinx ± bcosx is [-√a²+b², +√a²+b²] here a=1 & b=√3 then range is [-2,+2] +1 that equals [-2+1,+2+1]=[-1,3]

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