Anusha11 Years agoAns:- 3∫2 (2x2 +1)dx=2[(x2+1 /2+1)]23+[x]23=2[(x3 /3)]23 +[x]23=2[(33 /3)+(23 /3)]+[3-2]=2[(27+8)/3]+1=2[(35/3)]+1=(70/3)+1=73/3
Miryala Gopalakrishna11 Years agointegration of (2(X^2)+1)dx from 2 to 3 is equal to(2((x^3)/3)+x) from 2 to3=(2((3^3)/3)+3)-(2((2^3)/3)+2)=(2*(27/3)+3)-(2*(8/3)+2)=(18+3)-((16/3)+2)=(21)-(22/3)=41/3