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∫1/(1+x^3)

∫1/(1+x^3)


 

Grade:12

1 Answers

vikas askiitian expert
509 Points
11 years ago

 1+x^3 =(1+x)(1+x^2-x)

  now expression becomes

   dx/(x+1)(x^2+1-x)

  applying partial fraction

   1/3logx+1 -1/6log(x^2-x+1) +[taninverse{2x-1/(3^1/2)}]/(3^1/2)

 

 

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