Last Activity: 14 Years ago
From the graph , y+1 = x2 , we can say
between x=(0,1) y takes value of -1
x=(1,1.414) y takes value of 0
x=(1.414,1.732) y takes value of 1
x=(1.732,2) y takes value of 2
integrating in these limits gives
I = int ( -dx) + int ( 0*dx) + int ( dx) + int ( 2*dx) with above limits respecively
I = 1.732 - 1.414 = 0.218
--
regards
Ramesh
graph of [x^(2)-1]
integration is the area under the graph so its basically the area of the rectangle tht is 1*-1=1
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Year ago(s)