Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

integral sin{lim(t tends to 0)(2x/pie)cot(inverse)(x/t*t)} take limit from -pie/2 to pie/2

integral sin{lim(t tends to 0)(2x/pie)cot(inverse)(x/t*t)}


take limit from -pie/2 to pie/2

Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
7 years ago
Ans:0
I = \int_{-\pi /2}^{\pi /2}sin(\lim_{t\rightarrow 0}\frac{2x}{\pi }.\cot ^{-1}\frac{x}{t^{2}})dx
I = \int_{-\pi /2}^{\pi /2}sin(\lim_{t\rightarrow 0}\frac{2x}{\pi }.0)dx
I = \int_{-\pi /2}^{\pi /2}sin(0)dx
I = \int_{-\pi /2}^{\pi /2}0dx = 0
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free