Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The differential equation of all circles which passes through the origin and whose centre lies on y axis is

The differential equation of all circles which passes through the origin and whose centre lies on y axis is

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear pallavi

let the center is (o,a)  and  radius is r

so equation of circle is

x2 + (y-a)2 =r2

 differentiate

2x +2(y-a) dy/dx =0

x+ (y-a)dy/dx =0  ..............1

 

again differentiate

1+ (y-a)d2y/dx2 + dy/dx =0

put value of (y-a) from equation 1

1 -x(d2y/dx2)/(dy/dx) + dy/dx =0

(dy/dx )2 + dy/dx  - xd2y/dx2=0

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

 

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free